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ls -U1 now uses constant memory
When printing one name per line and not sorting, ls now uses constant memory per directory, no matter how many files are in the directory. * ls.c (print_dir): Print each file name immediately, when possible. * NEWS: Mention the improvement.
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committed by
Jim Meyering
parent
b44f5f74aa
commit
8d974b00fb
3
NEWS
3
NEWS
@@ -51,6 +51,9 @@ GNU coreutils NEWS -*- outline -*-
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join has significantly better performance due to better memory management
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ls now uses constant memory when not sorting and using one_per_line format,
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no matter how many files are in a given directory
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od now aligns fields across lines when printing multiple -t
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specifiers, and no longer prints fields that resulted entirely from
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padding the input out to the least common multiple width.
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14
src/ls.c
14
src/ls.c
@@ -2402,6 +2402,20 @@ print_dir (char const *name, char const *realname, bool command_line_arg)
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#endif
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total_blocks += gobble_file (next->d_name, type, D_INO (next),
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false, name);
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/* In this narrow case, print out each name right away, so
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ls uses constant memory while processing the entries of
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this directory. Useful when there are many (millions)
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of entries in a directory. */
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if (format == one_per_line && sort_type == sort_none)
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{
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/* We must call sort_files in spite of
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"sort_type == sort_none" for its initialization
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of the sorted_file vector. */
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sort_files ();
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print_current_files ();
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clear_files ();
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}
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}
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}
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else if (errno != 0)
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